Question

help me answer this please and also my other question​

Answer 1

$\bf P(t)=\dfrac{1}{1+15(2.1)^{0.3t}}$

Now

$\\ \sf\longmapsto P(4)=\dfrac{1}{1+15(2.1)^{0.3(4)}}$

$\\ \sf\longmapsto P(4)=\dfrac{1}{1+15(2.1)^{1.2}}$

$\\ \sf\longmapsto P(4)=\dfrac{1}{1+15(2.4)}$

$\\ \sf\longmapsto P(4)=\dfrac{1}{1+36}$

$\\ \sf\longmapsto P(4)=\dfrac{1}{37}$

And

$\\ \sf\longmapsto P(10)=\dfrac{1}{1+15(2.1)^{0.3(10)}}$

$\\ \sf\longmapsto P(10)=\dfrac{1}{1+15(2.1)^10}$

$\\ \sf\longmapsto P(10)=\dfrac{1}{1+15(9.2)}$

$\\ \sf\longmapsto P(10)=\dfrac{1}{1+138}$

$\\ \sf\longmapsto P(10)=\dfrac{1}{139}$