what is the solution of the following system -2x-y=1 -4x-2y=-1

-2x - y = 1 (1st)
-4x - 2y = -1 (2nd)
Multiply 1st equation by 2
-4x - 2y = 2
Now you have 2 new equations
-4x - 2y = 2
-4x - 2y = -1
----------------------Subtract
0 ≠ 3
Answer: No solutions
Answer: The correct option is
(B) no solution.
Step-by-step explanation: We are given to find the solution to the following system of equations :
[tex]-2x-y=1~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\-4x-2y=-1~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)[/tex]
From equation (i), we have
[tex]-2x-y=1\\\\\Rightarrow y=-2x-1~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)[/tex]
Substituting the value of y from equation (iii) in equation (ii), we get
[tex]-4x-2(-2x-1)=-1\\\\\Rightarrow -4x+4x+2=-1\\\\\Rightarrow 2=-1,[/tex]
which can never be possible.
Therefore, the given system of equations has no solution.
Option (B) is CORRECT.