When driver see the child standing on road his speed is 20 m/s
So here at that instant his reaction time is 0.80 s
He will cover a total distance given by product of speed and time
[tex]d_1 = v* t[/tex]
[tex]d_1 = 20 * 0.8[/tex]
[tex]d_1 = 16 m[/tex]
now after this he will apply brakes with acceleration a = 7 m/s^2
so the distance covered before it stop is given by
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
[tex]0 - 20^2 = 2*(-7)*d_2[/tex]
[tex]d_2 = 28.6 m[/tex]
so the total distance covered by it
[tex]d = d_1 + d_2[/tex]
[tex]d = 16 + 28.6 = 44.6 m[/tex]
so it will cover a total distance of 44.6 m