A sled travels 15 meters down a slope inclined at 30 degrees with a horizontal. What is the horizontal displacement of the sled?

Respuesta :

Length of the slope is given as

[tex]L = 15 m[/tex]

also the inclination is given as

[tex]\theta = 30 degree[/tex]

now the horizontal displacement is let say "x"

now from geometry we can say

[tex]\frac{x}{L} = cos30[/tex]

[tex]x = L cos30[/tex]

now substitute all values in it

[tex]x = 15 * cos30[/tex]

[tex]x = 12.99 m[/tex]

so it will displace horizontally by 12.99 m

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