The solution to given system of equations are [tex](x,y) = (\frac{4}{25} , \frac{123}{25})[/tex]
Solution:
Given that we have to find solution to the system of equations
Given equations are:
x + 2y = 10 ------ eqn 1
y = 12x + 3 ------ eqn 2
We can solve the above equations by substitution method
Substitute eqn 2 in eqn 1
x + 2(12x + 3) = 10
x + 24x + 6 = 10
25x = 10 - 6
25x = 4
[tex]x = \frac{4}{25}[/tex]
Substitute the above value of x in eqn 2
[tex]y = 12(\frac{4}{25}) + 3\\\\y = \frac{48}{25} + 3\\\\y = \frac{48+75}{25}\\\\y = \frac{123}{25}[/tex]
Thus the solution to given system of equations are [tex](x,y) = (\frac{4}{25} , \frac{123}{25})[/tex]