Question

A canister is filled with 310 g of ice and 100. G of liquid water, both at 0 ∘c . The canister is placed in an oven until all the h2o has boiled off and the canister is empty. How much energy in calories was absorbed?

Answer 1

Here in the process we require

1. Heat to melt down all ice

2. Heat to raise the temperature of whole water to 100 degree C

3. Heat to boil off the water

now here for the first part

Heat required to melt the ice

$Q_1 = mL$

$Q_1 = 310*80  = 24800 cal$

now heat required to raise the temperature to 100 degree C

$Q_2 = ms\Delta T$

$Q_2 = (310 + 100)*1*(100 - 0)$

$Q_2 = 41000 cal$

Now heat required to boil it off

$Q_3 = mL$

$Q_3 = 410*540 = 221400 cal$

now the total heat required will be

$Q = Q_1 + Q_2 + Q_3$

$Q = 24800 + 41000 + 221400$

$Q = 287200 cal$

so it required 287200 calorie heat to boil it all water