Question

Light travels from rarer medium 1 to a denser medium 2. The angle of incident and refraction are respectively 450 and 300. Calculate the (i) refractive index of second medium with respect to the first medium and (ii) refractive index of medium 1 with respect to the medium 2.

Answer 1

The refractive index of the second medium with respect to the first medium is 0.707. The refractive index of medium 1 with respect to medium 2 is  1.414.

The refractive index of an optical medium is a dimensionless wide variety that offers an indication of the light bending capacity of that medium. The refractive index determines how a good deal of the path of mild is bent or refracted while entering a material.

Angle of incidence = 45°

The angle of refraction = 30°

According to the laws of refraction = the angle of incidence/angle of refraction

Mediun 1 = rearer

Medium 2 = denser

(i) refractive index of the second medium with respect to the first medium

           refractive index = sin 30°/sin  45°

                                      = 1/2 / 1/$\sqrt{2$

                                      =   $\sqrt{2$/2

                                     = 0.707

(ii) refractive index of medium 1 with respect to the medium 2

           refractive index = sin 45°/sin  30°

                                      =  1/$\sqrt{2$/1/2

                                       = 2/√2

                                        = 1.414

Learn more about the refractive index here:-https://brainly.com/question/10729741

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