Since parachutist is moving downwards with constant speed
so here we can say
[tex]a = \frac{dv}{dt}[/tex]
acceleration is rate of change in velocity
since velocity is given constant here
[tex]a = 0[/tex]
So acceleration in this case will be zero
now we know from Newton's II law
[tex]F_{net} = ma[/tex]
here a = 0
[tex]F_{net} = 0[/tex]
[tex]F_{net} = F_g - F_b[/tex]
here
[tex]F_g [/tex]= force due to gravity
[tex]F_b[/tex] = force due to buoyancy
So here we can say
[tex]F_g - F_b = 0[/tex]
so
[tex]F_g = F_b[/tex]
so upward force on it will be balanced by downward force.