First I would put the equation into y = mx + b form. [tex]5y = - 2x + 12[/tex] [tex]y = \frac{ - 2}{5} x + \frac{12}{5} [/tex] The slope of a perpendicular line will be a negative reciprocal of the line it is perpendicular too. The slope for the new equation will be 5/2. Then we can use the point given to find the y intercept(b). [tex]5 = \frac{5}{2} (4) + b[/tex] [tex]5 = 10 + b[/tex] [tex] - 5 = b[/tex] Now we can write the final equation. [tex]y = \frac{5}{2} x - 5[/tex]
