We have to find the exact value of
[tex] cot( \frac{11 \pi}{6} ) [/tex]
And it can also be written as
[tex] cot(2 \pi - \frac{ \pi }{6} ) [/tex]
And
[tex] cot(2 \pi - \theta) = - cot \theta [/tex]
So we will get
[tex] cot(2 \pi - \frac{ \pi}{6} ) = -cot( \frac{ \pi }{6}) = - \sqrt 3 [/tex]
