What is the GCF of 44j^5k^4 and 121j^2k^6?
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[tex] 44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\
121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\
\text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4 [/tex]
The greatest common factor will be equal to 11j²k⁴.
The largest factor of the two numbers which divides both the numbers is called as greatest common factor or GCF.
Here we have two numbers
44j⁵k⁴ and 121j²k⁶
We will find the factors of the both the given expressions:-
44 j⁵ k⁴ = 2² x 11 x j⁵ x k⁴
121 j² k⁶ = 11² x j² x k⁶
We can see that the highest common factor among the factors are:-
= 11 j² k⁴
Therefore the greatest common factor will be equal to 11j²k⁴.
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