Question

simplify the complex fraction. y-1/y^2+y-6/y-6/y+3
A) (y-1)(y-2)/(y-6)(y+2)
B) y-1/(y-6)(y-2)
C) (y-1)(y-6)/(y+3)^2 (y-2)
D) (y-1)(y-6)/(y+3)(y-2)
I really need help on this

Answer 1

For this case we have the following complex fraction:
 $\frac{\frac{y-1}{y^2+y-6} }{\frac{y-6}{y+3}}$
 Using the double C method, we can rewrite the given fraction.
 We have then:
 $\frac{(y-1)(y+3)}{(y^2+y-6)(y-6)}$
 Then, we must factor the quadratic expression into the denominator.
 We have then:
 $\frac{(y-1)(y+3)}{(y-2)(y+3)(y-6)}$
 Finally, we cancel similar terms.
 We have then:
 $\frac{(y-1)}{(y-2)(y-6)}$
 Answer:
 the complex fraction simplified is:
 B) y-1/(y-6)(y-2)

Answer 2

Answer:

Step-by-step explanation:

   try to do a or b