#Me being lazy ,,20Points for correcting answer with Explanation

Answer:
Step-by-step explanation:
If the function is linear, then:
[tex]\dfrac{rise}{run}=constant[/tex]
[tex]rise=\Delta y=y_2-y_1\\\\run=\Delta x=x_2-x_1[/tex]
From the table we have pairs of points:
(-2, -5), (-1, -1)
(-1, -1), (0, 3)
(0, 3), (1, 7)
Substitute:
[tex]\dfrac{1-(-5)}{-1-(-2)}=\dfrac{4}{1}=4\\\\\dfrac{3-(-1)}{0-(-1)}=\dfrac{4}{1}=4\\\\\dfrac{7-3}{1-0}=\dfrac{4}{1}=4[/tex]
The ratios are the same. Therefore the function is a linear function.