Question

What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?

Answer 1

(-2+4)^2+(1-1)^2=r^2

Answer 2

Answer with Step-by-step explanation:

The equation of a circle having center at (a,b) and radius r is given by:

(x-a)²+(y-b)²=r²

We are given (a,b)=(-2,1)

(x+2)²+(y-1)²=r²

the circle passes through (-4,1)

(-4+2)²+(1-1)²=r²

2²=r²

⇒ r=2

Hence,  general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1) is:

(x+2)²+(y-1)²=4