Answer:
angle of rotation will be 60°
Step-by-step explanation:
The given matrix is
[tex]\begin{bmatrix}\frac{1}{2} & -\frac{\sqrt{3}}{2}\\ \frac{\sqrt{3}}{2} &\frac{1}{2}\end{bmatrix}[/tex]
And we have to find the angle of rotation.
Since matrix showing angle of rotation θ is denoted by
[tex]\begin{bmatrix}cos\theta &-sin\theta \\ sin\theta & cos\theta \end{bmatrix}[/tex]
Matrix for angle of rotation will be
[tex]\begin{bmatrix}cos60 &-sin60 \\ sin60 &cos60\end{bmatrix}[/tex]
Therefore, angle of rotation will be 60°