Question

QF Q1.) Solve the triangle.

Answer 1

C=180-A-B=180-69-40=71deg.

by sine rule

b/sinB=a/sinA
b=a/sinA*sinB
=15/sin(69)*sin(40)
= 10.33

c/sinC=a/sinA
c=a/sinA*sinC
=15/sin(69)*sin(71)
= 15.19