Respuesta :
The margin of error is z*SD/sqrt(n). z is the critical score for a 95% confidence interval, which is 1.96. SD = 0.7, and n = 800 (the sample size). Therefore the margin of error is 1.96*0.7/sqrt(800) = 0.049. This is an appropriately large sample size.
The correct answer is: As the sample size is appropriately large, the margin of error is ±0.049.
The correct answer is: As the sample size is appropriately large, the margin of error is ±0.049.
Answer:
C.
There is a 95% certainty that the sample mean will fall within the interval 2.65 to 2.75.
Step-by-step explanation:
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