Question

Find the total area of the regular pyramid.

Answer 1

check the picture below.

notice, the base of the "square" pyramid, is a square, and it has 4 triangular faces with a base of 2, and a height of √(10).

so the total surface area is the area of the base plus all 4 triangular faces' areas.

$\bf \stackrel{\textit{squarish base}}{(2\cdot 2)}~~~~+~~~~\stackrel{\textit{4 triangular faces}}{4\left[ \cfrac{1}{2}(2)(\sqrt{10}) \right]}$

Answer 2

Answer:

Area of the regular pyramid = 16.64 square units.

Step-by-step explanation:

Given  : Regular pyramid .

To find: Find the total area of the regular pyramid.

Solution : We have  given that regular pyramid.

Area = 4 ( area of triangle ) + area of base .

Area of the regular pyramid = 4 ( $\frac{1}{2} * base * height + side * side$.

Area of the regular pyramid =  $4(\frac{1}{2}* 2* \sqrt{10}  + 2*2$

Area of the regular pyramid =   $4( \sqrt{10} ) + 4$

Area of the regular pyramid =  (4 $( \sqrt{10} ) \+\ 1$.

Area of the regular pyramid = 16.64 square units.

Therefore, Area of the regular pyramid = 16.64 square units.