Question

A gas sample occupies 3.50 liters of volume at 20.°c. what volume will this gas occupy at 100°c (reported to three significant figures)?

Answer 1

Based on Charle's Law, we have
$\frac{V1}{V2} = \frac{T1}{T2}$
where, V and T are volume and temperature respectively. 

Now, given that, V1 = 3.5 L, T1 = $20 ^{0}C$ = 293 K and T2 = $100^{0}C$ = 373 K

∴ V2 = $\frac{(T2)X(V1)}{T1} = \frac{373 X 3.5}{293} = 4.556l$