The length of the side of the base is 6 units.
The volume of the pyramid is;
[tex]\rm Volume \ of \ pyramid=\dfrac{1}{3}\times height \times Base[/tex]
The pyramid shown below has a square base, a height of 7, and a volume of 84.
Substitute all the values in the formula
[tex]\rm Volume \ of \ pyramid=\dfrac{1}{3}\times height \times Base\\\\\rm84 =\dfrac{1}{3}\times height \times 7\\\\Height = \dfrac{84\times 3}{7}\\\\ Height = \dfrac{252}{7}\\\\Height =36[/tex]
The length of the side of the base is;
[tex]\rm Side\ length^2=height\\\\ Side\ length^2=36\\\\Side\ length^2=6^2\\\\Side\ length=6[/tex]
Hence, the length of the side of the base is 6 units.
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