Question

how can you solve p2 - 12 =p ?

Answer 1

P= 4 and -3
Move all the terms to the left side and set equal to zero. Then set each factor to zero.

Answer 2

$- {p}^{2} - 12 = p \\ {p}^{2} - 12 - p = 0 \\ {p}^{2} - p - 12 = 0$

Now, use the mid term splitting technique

${p}^{2} - 4p + 3p - 12 \\ = p(p - 4) + 3(p - 4) \\ = (p + 3)(p - 4)$


From here
we'll do the same thing we do to find the zeroes,


p+3=0 or p -4 =0

p = -3 or p = 4

Therefore
p = -3 and 4