SQ = square root
329 = 20 * SQ (273+ t)
Do the inverse of everything on the left
Divide by 20
Square your answer (329/20)
and subtract 273 from it
((329/20)^2)-273 = t
the temperature according to my calculations was -2.3975 degrees
The nearest degree, if my math is correct was -2 degrees.
I'm not sure how to graph the equation, or I can't graph it for you, rather. Try Desmos if you need to graph it.
Mark brainliest if I helped you
