Respuesta :
Given x^2-5x+c=7, the constant term c will be obtained using the formula:
c=(-b/2a)²
given that a=1 and b=-5 then plugging the values we shall have:
c=(-(-5)/2*1)²
c=(5/2)²
c=25/4
Answer: the constant is 25/4
c=(-b/2a)²
given that a=1 and b=-5 then plugging the values we shall have:
c=(-(-5)/2*1)²
c=(5/2)²
c=25/4
Answer: the constant is 25/4
Answer:
[tex]c=\frac{25}{4}[/tex]
Step-by-step explanation:
The given equation is:
[tex]x^2-5x+--=7[/tex]
Rewriting the above given equations, we have
[tex]x^2-5x+c=7[/tex] where c is the constant term that is used to complete the square.
Now, In order to get the constant term c, we use the formula that is
[tex]c=(\frac{-b}{2a})^2[/tex]
where [tex]a=1[/tex] and [tex]b=-5[/tex]
Substituting these values, we have
[tex]c=(\frac{-(-5)}{2(1)})^2[/tex]
[tex]c=(\frac{5}{2})^2[/tex]
[tex]c=\frac{25}{4}[/tex]
Thus, [tex]c=\frac{25}{4}[/tex] is the constant term that is used to complete the square.