Archaeologists use the radioactive decay of carbon-14 to estimate the age of fossils and can be used on samples of bone, cloth, wood and plant fibers. The half-life of carbon-14 is 5,730 years. Several human bones have been unearthed at an archaeological dig. 25% of the original carbon-14 isotope is remaining and scientists estimate the bones to be ___________ years old.

Respuesta :

the answer should be 11,460 because the first half-life leaves 50 percent left and the next half-life would leave 25 percent which dates the bones at 11,460 years old.

Answer:

The age of bones was estimated to be 11,462 years old.

Explanation:

Formula used :

[tex]N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}[/tex]

where,

[tex]N_o[/tex] = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

[tex]t_{\frac{1}{2}}[/tex] = half life of the isotope

[tex]\lambda[/tex] = decay constant

We have:

[tex]N_o[/tex] = x, N = 25% of x = 0.25 x

t = ? .[tex]t_{1/2}=5,730 years[/tex]

[tex]\lambda=\frac{0.693}{5,730 years}=0.000120942 year^{-1}[/tex]

Now put all the given values in this formula, we get

[tex]0.25x=x\times e^{-0.000120942 year^{-1}\times t}[/tex]

t = 11,462.4338 years ≈ 11,462 years

The age of bones was estimated to be 11,462 years old.

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