The number of combinations of n objects taken r at a time is determined by the following formula:
[tex]C(n,r)=\dfrac{n!}{r!(n-r)!}[/tex].
Consider
[tex]C(16,4)= \dfrac{16!}{4!(16-4)!}= \dfrac{16!}{4!12!} = \dfrac{16!}{12!(16-12)!} =C(16,12) [/tex].
Answer: Correct choice is B.
