Question

What is the reaction quotient for this reaction:

4A  2B + 3C?

A) Q = [B]03[C] 02/[A] 04


B) Q = [B]0[C] 03/[A] 04


C) Q = [B]02 [C] 03/[A] 04


D) Q = [A] 04/[B]02 [C] 03


E)Q = [A] 04/[B]03 [C] 02

Answer 1

The reaction is 4A = 2B + 3C

Q = Products / Reactions

If there are numbers in front of the molecules, they turn into exponents

So the answer is C) Q = [B]^2 [C]^ 3/  [A]^4

Answer 2

Answer:

C) Q = [B]02 [C] 03/[A] 04

Explanation:

Hello,

In this case, based on the Law of Mass action, which states that the product of the concentration of the products divided the product of the concentration of the reactants both to the stoichiometric coefficient power equals the reaction quotient, we obtain for the given reaction:

$4A<->2B+3C\\\\Q=\frac{[B]^2[C]^3}{[A]^4}$

Therefore, the answer is C).

Best regards.