Question

Please help me. I know 3^x but I’m confused how to figure out the other answers

Answer 1

well i can help you with one more which is 9x*3x/9x  Since 9*3=27 so 9x*3x=27x Then the 9x is still there ending up with 27x/9x which is your starting fraction :)

Answer 2

B, E, and F are the correct steps to solving the given exponential problem:$(9*3)=27 so ((9*3)/9)^x\\=3^x$