Question

What are the values that satisfy the trigonometric equation for: 0≤q≤2π ? 0 ≤ q ≤ 2 π ? sin(∅)+tan(−∅)

Answer 1

we have that
f(∅)=sin(∅)+tan(-∅)
for   0 ≤ ∅ ≤ 2 π

using a graph tool
see the attached figure

the solutions are
∅=0
∅=pi
∅=2pi