Question

Determine the oxidation state of the metal ion in [co(nh3)5br]2+. express your answer as an integer.

Answer 1

The oxidation state of the metal ion in [Co(NH₃)₅Br]²⁺ is +3.

What is oxidation state?

Oxidation state of any element tells about the number of electrons gets exchanged by that element.

Positive oxidation number tells about the number of electrons that losses and negative oxidation number tells about the gained number of electrons. For the given compound [Co(NH₃)₅Br]²⁺, let the oxidation state of the metal be x, oxidation state of NH₃ is 0 and of Br is -1, we calculate to find the value of x as:

x + 5(0) + (-1) = +2

x = 2 + 1

x = +3.

Hence oxidation state of Co is +3.

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https://brainly.com/question/8990767

Answer 2

The charge present after the gain or loss of an electron on an atom is called the oxidation number. The oxidation state of the metal ion is +3.

What is the oxidation state?

The oxidation number or the state represents the transferred electrons by the atom or the element in a molecule or compound.

The molecular formula of the compound is: $\rm [Co(NH_{3})_{5}Br]^{2+}$

If the oxidation number of the metal ion is x, the oxidation number of ammonia is 0, and the bromide ion is -1 then,

$\begin{aligned}\rm x + 5(0) + (-1) &= +2\\\\&= 2 + 1\\\\&= +3 \end{aligned}$

Therefore, +3 is the oxidation state of the metal ion.

Learn more about the oxidation state here:

https://brainly.com/question/14004737