A hot heater measures 20 in diameter. What is the area of a metal base for the water heater, assuming a 2 inch overhang around the base of the water heater
The diameter of the heater=20 in Diameter of the heater and the overhang=20+4=24 in the area of the base will therefore be: A=πr² A=π(24/2)² A=144π in² A~452.39 in²