We can use quadratic formula to determine the roots of the given quadratic equation.
The quadratic formula is:
[tex]x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a} [/tex]
b = coefficient of x term = 20
a = coefficient of squared term = 3
c = constant term = -7
Using the values, we get:
[tex]x= \frac{-20+- \sqrt{400-4(3)(-7)} }{2(3)} \\ \\
x= \frac{-20+- 22 }{6} \\ \\
x=-7 , x= \frac{1}{3} [/tex]
So, the correct answer to this question are option C and D
