Respuesta :
Well, to solve this problem, you have to isolate x. The first step of doing this is subtracting 0.6 from each side to leave the equation as N/5=1.4. Then, you need to multiply both sides by 5 to find N. N/5*5=N, and 1.4*5=7. That leaves the equation as N=7, so the value of N is 7.
Hope this helps!
-Raiden
Hope this helps!
-Raiden
The answer is: " 7 " .
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→ " n = 7 " .
_________________________________________________
Explanation:
_________________________________________________
Given:
_________________________________________________
" (n/5) + 0.6 = 2 " ; Solve for "n" ;
Subtract "0.6" from EACH SIDE of the equation:
(n/5) + 0.6 − 0.6 = 2 −0.6 ;
to get:
(n/5) = 1.4 ;
Multiply EACH SIDE by "5" ; to isolate "n" on one side of the equation;
& to solve for "n" ;
5 * (n/5) = 1.4 * 5 ;
to get:
__________________________________________
" n = 7 ".
__________________________________________
Method 2)
__________________________________________
Given: " (n/5) + 0.6 = 2 " ; Solve for "n" ;
Note that we have "fifths" (the "fraction, (n/5)" ;
→ and: "10ths" (the decimal, "0.6" = "6/10" ) ;
Multiply the entire equation (both sides) by "10" ; to get rid of both the "fraction" and the "decimal" ;
Note: We choose "10"; since "10" is the highest "fraction" (that is represented by a "decimal value"; that is: "6/10" ; {i.e., "0.6 = 6/10" ; as aforementioned} ;
→ and since: "5" is a factor of "10" ;
So, multiplying the entire equation by "10"; will get rid of both the "fraction" AND the "decimal" values:
→ 10 * { (n/5) + 0.6) } = 2 * (10) ;
___________________________________________________
Note the "distributive property" of multiplication:___________________________________________________a(b + c) = ab + ac ;
a(b – c) = ab – ac .___________________________________________________As such:
→ Consider the "left-hand side" of the equation:
__________________________________________
→ 10 * { (n/5) + 0.6) } ;
= [10 * (n/5) ] + [10 * 0.6] ;
= (10n / 5) + 6 ;
= (10/5)n + 6 ;
= 2n + 6 ;
So we rewrite the equation:
→ 2n + 6 = 2 * (10) ;
Let us consider the "right-hand side of the equation:
→ 2 * (10) = 20 .
________________________________________________
Rewrite the equation as:
→ 2n + 6 = 20 ;
Now, solve for "n" ;
________________________________________________
Variant # 1 ):
________________________________________________
→ 2n + 6 = 20 ;
Subtract "6" from EACH SIDE of the equation; as follows:
→ 2n + 6 − 6 = 20 − 6 ;
to get:
→ 2n = 14 ;
Now, divide each side of the equation by "2" ;
to isolate "n" on one side of the equation; & to solve for "n" ;
→ 2n / 2 = 14 / 2 ;
→ " n = 7 ".
____________________________________________________
Variant # 1 ):
____________________________________________________
→ 2n + 6 = 20 ;
____________________________________________________
Divide the entire question by "2" ; to simplify; as follows:
____________________________________________________
→ {2n + 6} / 2 = 20 / 2 ;
→ (2n/2) + (6/2) = (20/2 ) ;
→ n + 3 = 10 ;
Subtract "3" from EACH SIDE of the equation;
to isolate "n" on one side of the equation; & to solve for "n" ;
→ n + 3 − 3 = 10 − 3 ;
to get:
→ " n = 7 " .
_____________________________________________________
_________________________________________________
→ " n = 7 " .
_________________________________________________
Explanation:
_________________________________________________
Given:
_________________________________________________
" (n/5) + 0.6 = 2 " ; Solve for "n" ;
Subtract "0.6" from EACH SIDE of the equation:
(n/5) + 0.6 − 0.6 = 2 −0.6 ;
to get:
(n/5) = 1.4 ;
Multiply EACH SIDE by "5" ; to isolate "n" on one side of the equation;
& to solve for "n" ;
5 * (n/5) = 1.4 * 5 ;
to get:
__________________________________________
" n = 7 ".
__________________________________________
Method 2)
__________________________________________
Given: " (n/5) + 0.6 = 2 " ; Solve for "n" ;
Note that we have "fifths" (the "fraction, (n/5)" ;
→ and: "10ths" (the decimal, "0.6" = "6/10" ) ;
Multiply the entire equation (both sides) by "10" ; to get rid of both the "fraction" and the "decimal" ;
Note: We choose "10"; since "10" is the highest "fraction" (that is represented by a "decimal value"; that is: "6/10" ; {i.e., "0.6 = 6/10" ; as aforementioned} ;
→ and since: "5" is a factor of "10" ;
So, multiplying the entire equation by "10"; will get rid of both the "fraction" AND the "decimal" values:
→ 10 * { (n/5) + 0.6) } = 2 * (10) ;
___________________________________________________
Note the "distributive property" of multiplication:___________________________________________________a(b + c) = ab + ac ;
a(b – c) = ab – ac .___________________________________________________As such:
→ Consider the "left-hand side" of the equation:
__________________________________________
→ 10 * { (n/5) + 0.6) } ;
= [10 * (n/5) ] + [10 * 0.6] ;
= (10n / 5) + 6 ;
= (10/5)n + 6 ;
= 2n + 6 ;
So we rewrite the equation:
→ 2n + 6 = 2 * (10) ;
Let us consider the "right-hand side of the equation:
→ 2 * (10) = 20 .
________________________________________________
Rewrite the equation as:
→ 2n + 6 = 20 ;
Now, solve for "n" ;
________________________________________________
Variant # 1 ):
________________________________________________
→ 2n + 6 = 20 ;
Subtract "6" from EACH SIDE of the equation; as follows:
→ 2n + 6 − 6 = 20 − 6 ;
to get:
→ 2n = 14 ;
Now, divide each side of the equation by "2" ;
to isolate "n" on one side of the equation; & to solve for "n" ;
→ 2n / 2 = 14 / 2 ;
→ " n = 7 ".
____________________________________________________
Variant # 1 ):
____________________________________________________
→ 2n + 6 = 20 ;
____________________________________________________
Divide the entire question by "2" ; to simplify; as follows:
____________________________________________________
→ {2n + 6} / 2 = 20 / 2 ;
→ (2n/2) + (6/2) = (20/2 ) ;
→ n + 3 = 10 ;
Subtract "3" from EACH SIDE of the equation;
to isolate "n" on one side of the equation; & to solve for "n" ;
→ n + 3 − 3 = 10 − 3 ;
to get:
→ " n = 7 " .
_____________________________________________________