Consider the given right triangle.
We have to find the value of 'x'.
Consider [tex] \tan 40^{\circ} [/tex]
Since [tex] \tan \Theta =\frac{P}{B} [/tex]
[tex] \tan 40^{\circ} = \frac{x}{11} [/tex]
Finding the value of [tex] \tan 40^{\circ} [/tex] from the calculator,
We get
[tex] \tan 40^{\circ} = 0.84 [/tex]
Now, [tex] 0.84 = \frac{x}{11} [/tex]
[tex] x = 0.84 \times 11 [/tex]
x = 9.24
x = 9.2 (Rounded to nearest tenth)
So, the value of 'x' is 9.2 cm.
Option 3 is the correct answer.
