Question

A single die is rolled twice. find the probability of rolling an odd number the first time and a number less than 3 the second time.

Answer 1

hola!

Total outcomes of a die are { 1, 2, 3, 4, 5 and 6} = 6

→ for first case:
Favourable outcomes {1, 3, 5} = 3

P (rolling an Odd number the first time) = 3/6 = 1/2

→ for second case:
Favourable outcomes {1, 2} = 2

P (rolling a number less than 3 the second time) = 2/6 = 1/3

Thus,
The probability of getting both these events :

P ( both events ) = 1/2 × 1/3 = 1/6

hope it helps!

Answer 2

$|\Omega|=6^2=36\\ |A|=3\cdot2=6\\\\ P(A)=\dfrac{6}{36}=\dfrac{1}{6}\approx17\%$