Respuesta :
Answer:
72.25%; 23.16%; 76.84%; No.
Step-by-step explanation:
The probability that any given cheese chosen at random will be pasteurized is 85%, or 0.85.
This means that the probability of two random cheeses being pasteurized will be
0.85(0.85) = 0.7225 = 72.25%.
The probability that 9 cheeses chosen at random will all be pasteurized will be
0.85⁹ = 0.2316 = 23.16%.
The probability that at least 1 out of 9 cheeses chosen at random will be raw-milk would be the complement of no cheeses being raw milk. This means all 9 would be pasteurized; we know this probability to be 23.16%. This means the complement would be
1-0.2316 = 0.7684 = 76.84%.
1 out of 9 cheeses being raw-milk is 1/9 = 0.1111 = 11.11%.
85% of cheese are pasteurized; this means that 100-85 = 15% of cheeses are raw-milk. Thus an 11% probability would not be unusual.
a) 72.25%
b) 23.16%
c) 76.84%
d) No
Step-by-step explanation:
Given :
85% of cheeses are classified as pasteurized.
Calculation :
a) The probability that both cheeses are pasteurized is,
[tex]0.85\times0.85=0.7225\\[/tex]
=72.25%
b) The probability that all nine cheeses are pasteurized
[tex](0.85)^9=0.2316[/tex]
= 23.16%
c) The probability that at least one of nine randomly selected cheeses is raw dash milk is,
[tex]= 1-0.2316[/tex]
[tex]=0.7684[/tex]
= 76.84%
d) one out of nine cheeses are raw-milk is
[tex]\dfrac{1}{9} = 0.1111[/tex]
= 11.11%1/9
85% of cheese are pasteurized, this means that
100-85 = 15%
15 % of cheeses are raw-milk.
Thus an 11% probability would not be unusual.
No, it would not be unusual that at least one of nine randomly selected cheeses is raw dash milk.
For more information, refer the link given below
https://brainly.com/question/23343260?referrer=searchResults
