In a game the player wins if he rolls a 4 on a number cube.If the number cube is rolled 24 time,then what is the reasonable prediction for the number of unsuccessful rolls?

Respuesta :

Assuming that this is a regular six sided die, then the reason prediction for the number of losing rolls would be 20, as 1/6 * 24 = 4
24-4 = 20

The player wins if he rolls a 4 on the number cube.

Total number of outcomes on number cube = {1,2,3,4,5,6}

Probability of winning = [tex] \frac{1}{6} [/tex]

If the number cube is rolled 24 times.

Therefore, the reasonable prediction for the number of successful rolls

= [tex] \frac{1}{6} \times 24 [/tex]

= 4.

Therefore, the reasonable prediction for the number of unsuccessful rolls

= Number of times number cube rolled - reasonable prediction for the number of successful rolls

= 24 - 4

= 20.

Therefore, the reasonable prediction for the number of unsuccessful rolls is 20.

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