Question

There are many lewis structures you could draw for sulfuric acid, h2so4 (each h is bonded to an o). part a what lewis structure(s) would you draw to satisfy the octet rule? draw the molecule(s) by placing atoms on the grid and connecting them with bonds. include all lone pairs of electrons.

Answer 1

Structure 1 is satisfying octet rule because each atom surrounded by 8 electrons:
The valance electron for oxygen is 6, for sulfur is 6, but for hydrogen is 1. Therefore, the molecule has valance electrons. Sulfur is bonded with 4 oxygen atoms,  4 single bonds, whereas 2 hydrogen atoms are bonded with 2 oxygen atoms. 

But the actual structure is 2 but it violates octet rule since S is surrounded in this case with 12 electrons

Answer 2

The lewis structure that satisfies octet rule is structure 1. (Refer to attached image).

Further explanation:

The octet rule is the rule in accordance with which the elements have the tendency to bond with other elements and acquire eight electrons in their valence shells. This results in achieving a stable noble gas configuration.

The bonding between the different atoms in covalent molecules is shown by some diagrams known as the Lewis structures. These also show the presence of lone pairs in the molecule. These are also known as Lewis dot diagrams, electron dot diagrams, Lewis dot structures or Lewis dot formula. In covalent compounds, the geometry, polarity, and reactivity are predicted by these structures

The Lewis structures of ${{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$ is as follows:

The valance electron for oxygen is 6.

The valance electron for sulfur is 6.

The valance electron for hydrogen is 1.

Lewis structure of ${{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$ (Refer to the structure in the attached image):

The total number of valence electrons of ${{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$ is calculated as:

$\begin{aligned}{\text{Total valence electrons}}\left( {{\text{TVE}}} \right)&= \left[ {\left( 2 \right)\left( 1 \right)+\left(1\right)\left(6\right)+\left( 4 \right)\left( 6 \right)} \right]\\&= 32\\\end{aligned}$

Therefore, the molecule has 32 valance electrons. Sulfur is bonded with 4 oxygen atoms by 2 single bonds and 2 double bonds whereas 2 hydrogen atoms are bonded with 2 oxygen atoms. Therefore, 16 valence electrons form bond and 16 are present as lone pairs of electrons.

There are two Lewis structures for ${{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$. Structure 1 satisfies the octet rule because each atom surrounded by 8 electrons in the structure.

Also, the correct Lewis structure for ${{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$ is shown in structure 2. In this structure, S is surrounded by12 electrons as there are six bonds pairs and each bond carries two electrons. (Refer to attached image).

Learn more:

1. Identification of ionic bonding: https://brainly.com/question/1603987

2. What type of bond exists between phosphorus and chlorine? https://brainly.com/question/81715

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Molecular bonding and structure

Keywords: Lewis structure, valence electrons, Sulphur, hydrogen, oxygen, H2SO4, 32, and octet rule.