answers
b = 2.77 m
A = 43.0°
C = 111.1°
cosine law to find b
[tex]b^2 = a^2 + c^2 -2ac \cos B \\ \\
b = \sqrt{a^2 + c^2 -2ac \cos B} \\ \\
b = \sqrt{4.33^2 + 5.92^2 - 2(4.33)(5.92) \cos 25.9} \\
b = 2.7708\ m[/tex]
b = 2.7708\ m
Find angle A with sine law
[tex]\displaystyle
\frac{\sin A}{a} = \frac{\sin B}{b} \\ \\
\sin A = \frac{a \sin B}{b} \\ \\
A = \sin^{-1} \left[ \frac{a \sin B}{b} \right] \\ \\
A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708} \right] \\ \\
A = 43.0467020[/tex]
Find C with angles in triangle sum to 180
A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
C = 111.1
