Answer:
The solutions are -3 and -6
Explanation:
First we would need to put the equation in standard form which is:
ax² + bx + c = 0
This can be done as follows:
x² + 18 = -9x
x² + 9x + 18 = 0
By comparison, we would find that:
a = 1
b = 9
c = 18
Now, to get the roots, we would use the quadratic formula shown in the attached image.
By substitution, we would find that:
either x = [tex] \frac{-9+ \sqrt{(9)^2-4(1)(18)} }{2(1)} = -3[/tex]
or x = [tex] \frac{-9- \sqrt{(9)^2-4(1)(18)} }{2(1)} = -6[/tex]
Hope this helps :)
