Question

What is the distance between the points (38, 30) and (14, 20)

Answer 1

here's a formula to slove ur problem
√(x₁-x₂) +(y₁-y₂)
=√(38-14) +(30-20)
=√24+10
=√34

Answer 2

$p(a \: \: b) \: \: \: \: q(c \: \: d) \\ distance \: p \: q = \\ \sqrt{ {(a - c)}^{2} + {(b - d)}^{2} } \\ so.... \\ \sqrt{ {(38 - 14)}^{2} + {(30 - 20)}^{2} } = 26$
hope this would help you