since they are similar, their radius:angles ratio will be the same so set up a proportion: [tex] \frac{20\pi}{3} \div 4\pi = \frac{x}{9} \\ crossmultiply \\ 4\pi \times x = \frac{20\pi}{3} \times \frac{9}{1} [/tex] [tex]4\pi \times x = \frac{20\pi}{1} \times \frac{3}{1} \\ 4\pi \times x = 60\pi \\ \frac{4\pi \: x}{4\pi} = \frac{60\pi}{4\pi} \\ x = 15[/tex] B) 15 is your final answer