There is a common x in all those terms that can be factored out first to make our job a bit easier. Since this is a third degree polynomial, we are expecting to find 3 solution. Factoring out that x, what we are left with is [tex]x(x^2-2x-3)[/tex]. By the Zero Product Property, x=0 or [tex]x^2-2x-3=0[/tex]. We have one of our 3 solutions already. x = 0. We will factor the quadratic that remains to find the other 2 roots. The 2 numbers that add to -2 and multiply to -3 are (x-3)(x+1) which is to say that x=3 and x= -1. So all the roots of our polynomial are x = -1, 0, 3. There you go!
