Question

When 23 is subtracted from the square root of three times a number, the result is 16. find the number?

Answer 1

(√3n)-23=16

Put all of the numbers without a variable on the right side of the equation
(√3n)=39

Simplify 
1.732051n=39

Divide 39 by 1.732051
n=22.516658

Round
n=22.5

Answer 2

The number when 23 is subtracted from the square root of three times a number, and gives the result is 16 is 507

let

the number = n

three times a number

3 × n = 3n

square root of three times a number,

√3n

23 is subtracted

√3n - 23

result is 16

√3n - 23 = 16

solve for n

√3n = 16 + 23

√3n = 39

square both sides to eliminate square root

√3n = 39

(√3n)² = 39²

3n = 1521

n = 1521 / 3

n = 507

Therefore, the number is 507

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