Use the table below to find the percentage of data items in a normal distribution that lie a. below and b. above a​ z-score of 2.6.

Use the table below to find the percentage of data items in a normal distribution that lie a below and b above a zscore of 26 class=

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To answer the questions we use the z-table given.
a] The percentage of data items that lie below the z-score is given by:
P(z=2.6)=99.53
Answer: 99.53%

b] The percentage of data items that lie above the z-score is given by:
1-P(z=2.6)
P(z=2.6)=0.9953
thus
1-P(z=2.6)
=1-0.9953
=0.0047
=0.47%

a) The percentage of data items in a normal distribution that lie below a z score of 2.6 is 99.53%

b) The percentage of data items in a normal distribution that lie above a z score of 2.6 is 0.47%

Step-by-step explanation:

a) The percentage of data items in a normal distribution that lie below a z score of 2.6 is,

P(z = 2.6) = 99.53%

b) The percentage of data items in a normal distribution that lie above a z score of 2.6 is,

= 1 - P(z = 2.6)

= 1 - 0.9953

= 0.0047

= 0.47 %

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