Question

A ball was kicked into the air from a balcony 20
feet above the ground, and the ball’s height above
the ground, in feet, t seconds after the ball was
kicked was ℎ() = 20 − 162 + 32. What was the
maximum height, in feet, of the ball above the
ground after it was kicked?

Answer 1

Max ht is at the vertex of the parabola, at t = -b/2a
t = -32/-32 = 1
h(1) = -16 + 32 + 20
= 36 feet
hope this helps 

Answer 2

h(t) = (t) = - 16t^2  + 32t + 20
Maximum Height of parabola (vertex) 
t = - b/2a
t = - 32/- 32 = 1
h (1) = - 16 + 32 + 20
Answer = 36 Feet


Hope that answer your question, and helps you!!!