Question

Find the surface area of regular prism with height 6 cm, if the base of the prism is: Regular quadrilateral with side 4 cm.

Answer 1

A "regular quadrilateral" is a square, so the length and width are both 4 cm. The surface area of a rectangular prism is given by
  S = 2(LW +H(L +W))
  S = 2((4 cm)*(4 cm) +(6 cm)*(4 cm +4 cm))
  S = 2(16 cm² +48 cm²)
  S = 2*64 cm² = 128 cm²

The surface area of the prism is 128 cm².

Answer 2

Surface area of regular prism with height 6 cm, and Regular quadrilateral base with side 4 cm is 128 square cm.

What is regular prism?

A prism with bases that are regular polygons is called regular prism.

Here given that base of prism is regular quadrilateral so length of base = width of base =4cm

It's given that height of prism is 6cm

We know that surface area of regular prism is

$S=2[l \times w+ w\times h+h\times l]$

where

S= surface area

Where l= length of prism

w= width of prism

h= height of prism

Surface area of prism can be calculated as :

$S=2[4 \times 4 + 4\times 6 + 6\times 4]\\\\S=2[16+24+24]\\\\S=128\ cm^2$

Surface area of regular prism with height 6 cm, and Regular quadrilateral base with side 4 cm is 128 square cm.

To learn more about surface area visit :https://brainly.com/question/20771646