Question

Calculate the [oh−] value of each aqueous solution. oven cleaner, with [h3o+]=1.0×10−12m

Answer 1

The oven cleaner has [H⁺(aq)] as 1.0 x 10⁻¹² M. hence the pH of the solution can be calculated by using the equation , pH = -log₁₀[H⁺(aq)]
 hence, pH = -log₁₀(1.0 x 10⁻¹² M)
                  = 12

Since pH + pOH = 14
          12 + pOH = 14
                   pOH = 2

pOH         = -log₁₀[OH⁻(aq)]
   2           = -log₁₀[OH⁻(aq)]
[OH⁻(aq)] = 1.0 x 10⁻² M

Hence the [OH⁻] in oven cleaner is 1.0 x 10⁻² M