Question

What is the volume of a gas that exerts a pressure of 457 mm hg if it exerted a pressure of 2.50 atm when its volume was 25.0 ml?

Answer 1

  The  volume  of  gas  that   exerts   a pressure  of  457 mmhg   if  exerted  a  pressure  of  2.50  atm  when  its  volume  was  25.0ml  is  calculated  as follows
 
by  use  of  Bolyes law  formula  that  is  P1V1=P2V2
P1= 457mmhg
V1=?
P1 =  2.50  atm  =   2.50  x760 =  1900mmhg
V2=  25,0 ml

V1  from the formula  above =  P2V2/P1
=  1900mm hg  x25  ml/  457 mm hg = 104 ml

Answer 2

$\boxed{{\text{103}}{\text{.94 mL}}}$ of gas exerts a pressure of 457 mm Hg.

Further Explanation:

Ideal gas:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept, and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure.

Ideal gas law is considered as the equation of state for any hypothetical gas. The expression for the ideal gas equation of gas is as follows:

${\text{PV}}={\text{nRT}}$                          …… (1)

Here,

P is the pressure of the gas.

V is the volume of gas.

n denotes the number of moles of gas.

R is the gas constant.

T is the temperature of gas.

Boyle’s law:

It is an experimental gas law that describes the relationship between pressure and volume of the gas. According to Boyle's law, the volume of the gas is inversely proportional to the pressure of the system, provided that the temperature and the number of moles of gas remain constant.

If the temperature and number of moles of gas are constant then the equation (1) will become as follows:

${\text{PV}}={\text{constant}}$                          …… (2)

Or it can also be expressed as follows:

${{\text{P}}_1}{{\text{V}}_1}={{\text{P}}_2}{{\text{V}}_2}$                         …… (3)

Here,

${{\text{P}}_1}$ is the initial pressure.

${{\text{P}}_2}$ is the final pressure.

${{\text{V}}_1}$ is the initial volume.

${{\text{V}}_2}$ is the final volume.

Rearrange the equation (3) for ${{\text{P}}_2}$  , and we get,

${{\text{P}}_2}=\frac{{{{\text{P}}_1}{{\text{V}}_1}}}{{{{\text{V}}_2}}}$                                              …… (4)

The conversion factor to convert ${\text{atm}}$ into ${\text{mm Hg}}$ is as follows:

${\text{1 atm}}={\text{760 mm Hg}}$

The value of ${{\text{P}}_1}$ is 2.50 atm.

The value of ${{\text{V}}_1}$  is 25 mL.

The value of ${{\text{P}}_2}$  is 457 mm Hg.

Substitute these values in equation (4).

$\begin{aligned}{{\text{V}}_{\text{2}}}&=\frac{{\left( {{\text{2}}{\text{.50 atm}}}\right)\left({\frac{{760\;{\text{mmHg}}}}{{{\text{1}}\;{\text{atm}}}}}\right)\left({{\text{25 mL}}}\right)}}{{\left( {457\;{\text{mmHg}}}\right)}}\\&= {\text{103}}{\text{.938731 mL}}\\&\simeq {\text{103}}{\text{.94 mL}}\\\end{aligned}$

The final volume of a gas is 103.94 mL.

Learn more:

1. Determine the final pressure of the ideal gas: https://brainly.com/question/6340739

2. Chemical bonds in NaCl: https://brainly.com/question/5008811

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: ideal gas, pressure, volume, absolute temperature, equation of state, hypothetical, universal gas constant, moles of gas, initial, final.