Question

three consecutive multiples of 4 whose sum is 52

Answer 1

I know that 4x13=52 but I don’t know 3 more

Answer 2

Solution:

Let the three consecutive multiples of 4 be 4x, 4(x+1) and 4(x+2)

Then we can write

$4x+4(x+1)+4(x+2)=52\\ \\ x+x+1+x+2=52/4\\ \\ 3x+3=13\\ \\ 3x=10\\ \\ x=\frac{10}{3}$

As 10/3 is not a multiple of 4. Hence no consecutive multiples are possible.