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Let the price of a pair of skis = x , and the price of a pair of skates = y
The price of 3 pairs of skis and 4 pairs of skates was $470
∴ 3x + 4y = 470 ⇒⇒⇒ (1)
The price of 2 pairs of skates is $10 more than the price of a pair of skis
∴ 2y - x = 10 ⇒⇒⇒ (2)
multiplying equation (2) by 3 and add to equation (1)
∴ 10y = 500
∴ y = 50
Substituting at (2) to find x
∴ x = 2y - 10 = 90
The price of a pair of skis = 90
The price of a pair of skates = 50
The price of 3 pairs of skis and 4 pairs of skates was $470
∴ 3x + 4y = 470 ⇒⇒⇒ (1)
The price of 2 pairs of skates is $10 more than the price of a pair of skis
∴ 2y - x = 10 ⇒⇒⇒ (2)
multiplying equation (2) by 3 and add to equation (1)
∴ 10y = 500
∴ y = 50
Substituting at (2) to find x
∴ x = 2y - 10 = 90
The price of a pair of skis = 90
The price of a pair of skates = 50
The price of a pair of skis is $90 and a pair of skates $50.
Given that
The price of 3 pairs of skis and 4 pairs of skates was $470.
We have to determine
What is the price of a pair of skis and a pair of skates if the price of 2 pairs of skates is $10 more than the price of a pair of skis?
According to the question
Let the price of the pairs of skis be x,
And the price of the pair of skates is y.
The price of 3 pairs of skis and 4 pairs of skates was $470.
[tex] \rm 3x + 4y = 470[/tex]
If the price of 2 pairs of skates is $10 more than the price of a pair of skis.
[tex]\rm 2y - x = 10[/tex]
On solving both the equations
From equation 2;
[tex]\rm 2y - x = 10\\ \\ 2y-10=x\\ \\ x = 2y-10[/tex]
Substitute the value of x in equation 1.
[tex] \rm 3x + 4y = 470\\ \\ 3(2y-10) +4y = 470\\ \\ 6y - 30 +4y = 470\\ \\ 10y = 470+30\\ \\ 10y=500\\ \\ y = \dfrac{500}{10}\\ \\ y = 50[/tex]
Substitute the value of y in equation 2,
[tex]\rm 2y-x=10\\ \\ 2(50)-x=10\\ \\ 100-x=10\\ \\ -x=10-100\\ \\ -x=-90\\ \\ x=90[/tex]
Hence, the price of a pair of skis is $90 and a pair of skates $50.
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https://brainly.com/question/724536